Getting servlet init parameter that is defined in web.xml

1. Create a new dynamic web project using eclipse.
2. Create a one new servlet and include the following code.

package com.controller;

import java.io.IOException;

import javax.servlet.ServletConfig;

import javax.servlet.ServletException;

import javax.servlet.annotation.WebServlet;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

@WebServlet("/LoginController")

public class LoginController extends HttpServlet {

                private static final long serialVersionUID = 1L;

                public LoginController() {

        super();

    }

    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

                                ServletConfig config = getServletConfig();

                                System.out.println("Init parameter user name: " + config.getInitParameter("userName"));

                                System.out.println("Init parameter password: " + config.getInitParameter("password"));

                }

}

3. Update the web.xml file with following content.

<servlet>

      <servlet-name>LoginController</servlet-name>

      <servlet-class>com.controller.LoginController</servlet-class>

      <init-param>

            <param-name>userName</param-name>

            <param-value>admin</param-value>

      </init-param>

      <init-param>

            <param-name>password</param-name>

            <param-value>password</param-value>

      </init-param>

  </servlet>

  <servlet-mapping>

      <servlet-name>LoginController</servlet-name>

      <url-pattern>/loginController</url-pattern>

  </servlet-mapping>

4. Run the servelet through browser, you can able to get the user name and password from servlet init parameter.